The
list of practice Aptitude Questions with Solutions for SSC / FCI Exams were
given here, candidates those who are preparing for the examination can use this
practice questions
1).A
publisher printed 2000copies of a book at a total cost of Rs.6000.He
distributed 100 copies to institutions as free samples and sold the remaining
at the rate of Rs.4 per copy. His gain or loss percent is
a) 26 1/3% Gain
b) 26 1/3%Loss
c) 26 2/3%Gain
d) 26 2/3%Loss
Explanation
Remaining copies after free distribution 2000-100 =1900 Sales proceeds of 1900 copies =1900×4=7600.00 ∴Profit =7600-6000 =1600 ∴Percentage of profit =1600/6000×100 =26 2/3 %gain
2).7% of the selling price of an article is equal to 8% of its cost price; 9%of the selling price exceeds 10% of its cost price by Rs.2.The amount of profit or loss is
a) Rs.85 profit
b) Rs.90 profit
c) Rs.100 loss
d) Rs.100 profit
Explanation
(7/100)x = (8/100)y or (7/100)x – (8/100)y = 0 ----------------à(1) (9/100)x – (10/100)y = 2 ---------------------------------à(2) 7x - 8y= 0 --------à(1) ×10 9x - 10y = 200 ----------à(2)×8 70x - 80y =0 72x - 80y = 1600 2x=1600 ∴x=800 Applying the value of x in the equation (1) 5600 - 8y=0 5600 = 8y; y=700 ∴Profit= S.P.- C.P= 800 - 700 =100
3).In
a party the ratio of the number of ladies to that of gents is 1:3;if 3 ladies
and 2 gents also join the party, the ratio is 1:2.The latest strength in the
party is
a) 25
b) 19
c) 21
d) 20
Explanation
Original Ratio 1:3 Let us take the actual number as x : 3x Now 3 ladies and 2 gents join The new ratio is x+3 : 3x+2 But the actual ratio is 1:2 ∴x+3 : 3x+2 = 1.2 2x+6=3x+2 4=x Now the ladies 4+3 =7 Gents 3×4+2 =14 Total =21
4).Find the value of (4.12×4.12 - 3.12×3.12) / (4.12 - 3.12)
a) 7.24
b) 17
c) 27
d) 47
Explanation
(a2-b2 )/(a-b) = a+b ∴4.12+3.12 =7.24
5).The average weight of 7 persons decreases by 2 kg if a person with weight 73 kg is replaced by another person. The weight of the new person is
a) 57 kg
b) 55 kg
c) 59 kg
d) 58 kg
Explanation
Let total weight of 7 persons be 7x 7x-14 =7x-73+y -14+73=y 59 =y
6).The average of 200 items was 50.Later on, it was discovered that two items were misread as 92 and 8 instead of 192 and 88.The correct average is
a) 50.7
b) 50.9
c) 50.3
d) 50.2
Explanation
Total of 200 items =200×50 =10000 Now the difference in misreading 192+88-92-8 =180 The new total =10000+180 =10180 ∴The new average =10180/200 =50.9
7).A square is converted into a rectangle by increasing the length of the square by 15% and decreasing its breath by 15%.What is the ratio of the area of the rectangle to that of the square?
a) 371/400
b) 391/400
c) 39/40
d) 351/400
Explanation
Let the side of the square be 100 ∴area=10000 Now the area of the rectangle 115×85 =9775 The ratio is 9775/10000 =391/400
8).If
a person pays Rs.60 every month for 5 years, at the rate of 10% simple
interest, what is the actual amount of interest he is to get?
a) Rs.1,800
b) Rs.3,600
c) Rs.915
d) Rs.900
Explanation
I= P × [n(n+1)] / (2 ×12) × r/100 =60 × (60×61)/(2 ×12) × 10/100 =915
9).A solid cylinder has total surface area of 231 cm2.Its covered surface area is two-thirds of the total surface area. The volume of the cylinder is:
a) 266.25cm2
b) 268 cm2
c) 269.5 cm2
d) None of these
Explanation
231=2πr2+2 rl 154 =2 πrl ∴l=154/2πr ____________(1) ∴77=22πr2 49/4 =r2 7/2 =r Apply this equation________(1) We get (154×7×2)/(2×22×7) =7 Volume of a cylinder =πr2l =22/7 × 49/7 × 7 =269.5 cm2
10).How many lead shots each of 0.3 cm. in a diameter can be made from a cuboids of dimensions 9cm ×11cm ×12cm?
a) 81,000
b) 75,000
c) 80,000
d) 84,000
Explanation
(9×11×12) / (4/3)πr2 = (9 ×11× 12 ×3× 7) / (4× 22 ×.15 ×.15 ×.15) =567/.045 =.84,000
Answers:
1). c) 2). d) 3). c) 4). a) 5). c) 6). b) 7). b) 8). c) 9). c)
10). d)
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